Here's a integral where I have to use trigonometric substitution but I can't get the right answer.(adsbygoogle = window.adsbygoogle || []).push({});

[int a=0 b=3] 1/(sqrt[9-x^2]) dx

I did the limit as t approches 3 from the left.

Then i did my trigonometric substitution, and it gives me arcsin(x/3).

Then i computed what i had arcsin(a/3)-arcsin(0/3).

It gives me 1.57 (estimated) or Pie/2 (real)

But in the answer sheet, it says 9pie/4...

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# Homework Help: Trigonometric + Improper

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