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Trigonometric Integration

  1. Jan 28, 2008 #1
    1. The problem statement, all variables and given/known data


    3. The attempt at a solution
    I tried all the u subs u=tanx and u=secx
    but neither worked.
    Should I used other methods?
    Please help me with the start!
  2. jcsd
  3. Jan 28, 2008 #2


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    Science Advisor

    You might try reducing this to sine and cosine. sec x= 1/cos x and tan x = sin x/cos x so this is
    [tex]\int \frac{1}{cos x}\frac{cos^2 x}{sin^2 x} dx= \int \frac{cos x}{sin^2 x} dx[/tex]

    Anything come to mind now?
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