# Trigonometric Problem

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Hello, I'm in need of a hint or few pointers on how to calculate the angle C of the picture attached. I've already calculated y.

I was doing a few problems in this Dynamics book, i bought recently, and the ascention angle (angle C) is beating me "The airplane C is being tracked down by the radar stations A and B. At the instant shown on the picture, the triangle ABC encounters itself in vertical plane and the lectures are Angle A = 30 degrees, Angle B = 22 degrees, Angular Speed A = 0.026 rad/s, Angular Speed B = 0.032 rad/s. Find a) the height y, b) the magnitude of the velocity (the vector V is at point C directed at an ascention angle (angle C) with respect tot he horizontal c) the ascention angle at the instant shown (angle c)"

ah yes distance d = 1000 m and it's between the stations A and B.

I hope the diagram is clear enough...

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arildno
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Dearly Missed
A few hints:
1) Having "y", it is easy determine lengths of AC, BC, and form the vector from A to C, and the vector from B to C.
Let for example the vector from AC have the form $$\vec{r}_{AC}=r_{AC}\hat{r}_{AC}$$
where $$r_{AC},\hat{r}_{AC}$$ are the length and direction vector, respectively.

2) Let $$\hat{n}_{AC}$$ be the unit vector in the plane of the triangle perpendicular to $$\hat{r}_{AC}$$ and pointing in the direction of increasing angle, and make a similar construction for $$\hat{n}_{BC}$$

$$\vec{v}=v_{AC}\hat{r}_{AC}+v_{BC}\hat{r}_{BC}$$

4) We therefore have, for example the equality:
$$\vec{v}\cdot\hat{n}_{AC}=r_{AC}\omega_{AC}\to{v}_{BC}\hat{r}_{BC}\cdot\hat{n}_{AC}}=r_{AC}\omega_{AC}\to{v}_{BC}=\frac{r_{AC}\omega_{AC}}{\hat{r}_{BC}\cdot\hat{n}_{AC}}$$
where $$\omega_{AC}$$ is the angular velocity measured at A.

5) Thus, we have determined $$\vec{v}$$ and may answer the two remaining questions.
Remember that $$\hat{r}_{AC},\hat{r}_{BC}$$ are not orthogonal vectors!

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Homework Helper
Thanks Arildno, i was able to solve it. 