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Trigonometric Substitution Problem w/ Sin Substitution
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[QUOTE="Simon Bridge, post: 5624285, member: 367532"] This reads: $$\int \frac{\sqrt{64-x^2}}{x}\; dx$$ ... is that correct? If so, then sub ##x=8\sin\theta## does get you ##dx = 8\cos\theta\; d\theta## To give: $$8\int \frac{\cos^2\theta}{\sin\theta}\; d\theta$$ ... which is as far as you've got. You need to use trig identities to turn this into integrals you know how to do ... how about ##\cos^2\theta = 1-\sin^2\theta## ? The integrand is also ##\cos\theta / \tan\theta## and other forms you may have some luck figuring out. Basically you need to find a big table of trig identities and integrals. [/QUOTE]
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Trigonometric Substitution Problem w/ Sin Substitution
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