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http://img219.imageshack.us/my.php?image=utennavnwv7.jpg

- #2

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I should probably mention that the answer is supposed to be:

2*arctan(2x)+4x/(4x^2+1) +C

2*arctan(2x)+4x/(4x^2+1) +C

- #3

HallsofIvy

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You don't need the square root to apply a trig substitution. Let 2x= tan t and 4x

[tex]\int\frac{8dx}{(4x^2+ 1)^2}= \int \frac{4dt}{sec^2 t}= 4\int cos^2 t dt[/itex]

That should be easy.

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