Trigonometry and Logarithms

  • Thread starter Petkovsky
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62
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Main Question or Discussion Point

4[tex]^{sinx}[/tex] = [tex]\sqrt[cosx]{2}[/tex]

I use logarithmic and i get :

sinx * log(4) = (1/cosx) * log(2)

sinx*cosx = log(2)/log(4)


what should i do next?
 

Answers and Replies

737
0
What is log(2)/log(4)? Try applying a change of base rule. Afterward, see if you can use any of your trigonometric formulas to simplify.
 
454
0
4[tex]^{sinx}[/tex] = [tex]\sqrt[cosx]{2}[/tex]

I use logarithmic and i get :

sinx * log(4) = (1/cosx) * log(2)

sinx*cosx = log(2)/log(4)


what should i do next?
What is log(2)/log(4) ?
 
62
0
Thank you, i solved it
 

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