Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Trigonometry assistance

  1. Aug 18, 2005 #1
    How do I go about finding the equivalent expression for cot 50 degrees?

    When I work the problem, I come up with tan 130 degrees.

    Where am I going wrong?
  2. jcsd
  3. Aug 18, 2005 #2


    User Avatar
    Homework Helper

    I rather work in radians, if you don't mind.

    [tex]50^\circ = \frac{{5\pi }}{{18}}[/tex]

    We know that:
    [tex]\cot \left( \alpha \right) = \tan \left( {\frac{\pi }{2} - \alpha } \right)[/tex]

    [tex]\cot \left( {\frac{{5\pi }}{{18}}} \right) = \tan \left( {\frac{\pi }{2} - \frac{{5\pi }}{{18}}} \right) = \tan \left( {\frac{{2\pi }}{9}} \right) = \tan \left( {40^\circ } \right)[/tex]
  4. Aug 18, 2005 #3
    That makes perfect sense now.....

    The light has come on, thank you
  5. Aug 18, 2005 #4


    User Avatar
    Homework Helper

    No problem :smile:
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Trigonometry assistance
  1. Trigonometry Question (Replies: 7)

  2. Basic trigonometry (Replies: 5)