# Trigonometry basis

Physicsissuef

## Homework Statement

I have one trigonometry circular, like on this "[PLAIN [Broken] 00211.jpg"]picture.[/URL]

On the picture there are pi/2 and -pi/2.

Also I have another picture with inequality which "[PLAIN [Broken] 00211.jpg"]I need to solve.[/URL]

## The Attempt at a Solution

$$\sqrt{3}tg(3x+\frac{\pi}{3})<3$$

$$tg(3x+\frac{pi}{3})<\sqrt{3}$$

I have another "[URL [Broken] 0021111.JPG"]picture.[/URL]

So the results for tg are:

$$\frac{\pi}{3}>3x+\frac{pi}{3}>\frac{-\pi}{2}$$

so the results for x are

$$0>\frac{-5\pi}{18}$$

The question is: will I get same if I use $$\frac{3\pi}{2}$$ instead of $$\frac{\-pi}{2}$$

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Homework Helper
Hi Physicsissuef!

what is x? is it an angle (if it isn't, how can you add it to π/2?)

what are the two horizontal lines supposed to be?

what are you being asked to solve?

Physicsissuef
x is angle. I asked why I don't get same when I use $$\frac{3\pi}{2}$$ instead of $$\frac{-\pi}{2}$$???