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Trigonometry basis

  1. Apr 27, 2008 #1
    1. The problem statement, all variables and given/known data

    I have one trigonometry circular, like on this picture.

    On the picture there are pi/2 and -pi/2.

    Also I have another picture with inequality which I need to solve.

    2. Relevant equations



    3. The attempt at a solution

    [tex]\sqrt{3}tg(3x+\frac{\pi}{3})<3[/tex]

    [tex]tg(3x+\frac{pi}{3})<\sqrt{3}[/tex]


    I have another picture.

    So the results for tg are:

    [tex]\frac{\pi}{3}>3x+\frac{pi}{3}>\frac{-\pi}{2}[/tex]

    so the results for x are

    [tex]0>\frac{-5\pi}{18}[/tex]

    The question is: will I get same if I use [tex]\frac{3\pi}{2}[/tex] instead of [tex]\frac{\-pi}{2}[/tex]
     
  2. jcsd
  3. Apr 28, 2008 #2

    tiny-tim

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    Science Advisor
    Homework Helper

    Hi Physicsissuef! :smile:

    more information needed …

    what is x? is it an angle (if it isn't, how can you add it to π/2?)

    what are the two horizontal lines supposed to be?

    what are you being asked to solve? :confused:
     
  4. Apr 28, 2008 #3
    x is angle. I asked why I don't get same when I use [tex]\frac{3\pi}{2}[/tex] instead of [tex]\frac{-\pi}{2}[/tex]???
     
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