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Trigonometry basis

1. Homework Statement

I have one trigonometry circular, like on this "[PLAIN [Broken] 00211.jpg"]picture.[/URL]

On the picture there are pi/2 and -pi/2.

Also I have another picture with inequality which "[PLAIN [Broken] 00211.jpg"]I need to solve.[/URL]

2. Homework Equations



3. The Attempt at a Solution

[tex]\sqrt{3}tg(3x+\frac{\pi}{3})<3[/tex]

[tex]tg(3x+\frac{pi}{3})<\sqrt{3}[/tex]


I have another "[URL [Broken] 0021111.JPG"]picture.[/URL]

So the results for tg are:

[tex]\frac{\pi}{3}>3x+\frac{pi}{3}>\frac{-\pi}{2}[/tex]

so the results for x are

[tex]0>\frac{-5\pi}{18}[/tex]

The question is: will I get same if I use [tex]\frac{3\pi}{2}[/tex] instead of [tex]\frac{\-pi}{2}[/tex]
 
Last edited by a moderator:

Answers and Replies

tiny-tim
Science Advisor
Homework Helper
25,789
249
Hi Physicsissuef! :smile:

more information needed …

what is x? is it an angle (if it isn't, how can you add it to π/2?)

what are the two horizontal lines supposed to be?

what are you being asked to solve? :confused:
 
x is angle. I asked why I don't get same when I use [tex]\frac{3\pi}{2}[/tex] instead of [tex]\frac{-\pi}{2}[/tex]???
 

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