- #1
pavadrin
- 156
- 0
hey i have a problem which I am puzzled over. i I am given that:
[tex]\sin A = \frac{3}{5}[/tex]
and i am asked to find exact values for:
[tex]\sin 2A[/tex]
[tex]\cos 2A[/tex]
[tex]\tan 2A[/tex]
where [tex]90^0 \leq A \leq 180^0[/tex] (the power to zero is the degree sign)
i have gone about solving this by the use of a pythagorien (?) triple, therefore
[tex]\cos A = \frac{4}{5}[/tex] and
[tex]\tan A = \frac{3}{4}[/tex].
however i do not understand how A can be greator than 90 since this is in a right angle triangle. thanks in advance for those who help,
Pavadrin.
[tex]\sin A = \frac{3}{5}[/tex]
and i am asked to find exact values for:
[tex]\sin 2A[/tex]
[tex]\cos 2A[/tex]
[tex]\tan 2A[/tex]
where [tex]90^0 \leq A \leq 180^0[/tex] (the power to zero is the degree sign)
i have gone about solving this by the use of a pythagorien (?) triple, therefore
[tex]\cos A = \frac{4}{5}[/tex] and
[tex]\tan A = \frac{3}{4}[/tex].
however i do not understand how A can be greator than 90 since this is in a right angle triangle. thanks in advance for those who help,
Pavadrin.