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Trigonometry inequality

  1. Oct 7, 2016 #1
    1. The problem statement, all variables and given/known data
    show that 1-t^2/2 <=cos(t) <=1 for 0<=t<=1

    2. Relevant equations
    Trigonometry knowledge

    3. The attempt at a solution
    I don't know how to relate t with cos(t), and I also try to find out cos(1), but there is no result, so how can I start with this problem.
     
  2. jcsd
  3. Oct 7, 2016 #2

    SammyS

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    Staff Emeritus
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    Are you sure that it's 0 ≤ t ≤ 1 , and not 0 ≤ t ≤ π/2 ?
     
  4. Oct 7, 2016 #3
    Yes, this is what the question said. How can you solve for 0 <= t <= pi/2 ?
     
  5. Oct 7, 2016 #4
  6. Oct 7, 2016 #5

    Mark44

    Staff: Mentor

    Have you know about Maclaurin series yet, and in particular, the Maclaurin series for cos(t)?

    From another question you posted, you are taking a calculus class. If so, both questions should have been posted in the Calculus & Beyond section, not the Precalculus section.
     
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