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Trigonometry Question

  1. Mar 17, 2012 #1
    6845584594_d3e6579f2e_z.jpg
     
  2. jcsd
  3. Mar 18, 2012 #2

    LCKurtz

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    Try this:

    ##-1\le \cos x \le 1##

    ##-\frac 5 4 \le \cos x - \frac 1 4 \le \frac 3 4##

    ##0\le (\cos x - \frac 1 4)^2 \le \frac {25} {16}##

    ##0\ge -2(\cos x - \frac 1 4)^2\ge -\frac {25} 8##

    ##\frac 9 8 \ge \frac 9 8 -2(\cos x - \frac 1 4)^2\ge -\frac {16} 8 = -2##

    Think about what that gives.
     
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