1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Trigonometry - quick question

  1. May 11, 2005 #1
    I have a straight-forward question. Could anybody please explain me why...

    [tex]\theta = \tan ^{-1} \left( \frac{x}{2} \right) \Rightarrow -\frac{1}{4\sin \theta} = -\frac{\sqrt{x^2+4}}{4x} [/tex]

  2. jcsd
  3. May 11, 2005 #2
    Draw a triangle. Your vertical side will be x, your horizontal base will be 2. This is directly from the tan function. From there you can use pythagorean theorem to find the hypotenuse. Now you have all three sides, and you're trying to find

    [tex] -4csc(\theta)[/tex]. Just pull it right off the triangle. CSC is hyp/opp.
  4. May 11, 2005 #3
    One sec. after I posted it I realized what to do. Thanks, anyway.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Similar Discussions: Trigonometry - quick question
  1. Trigonometry Question (Replies: 3)

  2. Trigonometry Question (Replies: 14)

  3. Trigonometry Question! (Replies: 3)

  4. Trigonometry Question (Replies: 3)

  5. Trigonometry question (Replies: 5)