Solved:Trip to the moon 1. The problem statement, all variables and given/known data You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the earth with enough speed to make it to the moon. Some information that will help during this problem: mearth = 5.9742 x 10^24 kg rearth = 6.3781 x 10^6 m mmoon = 7.36 x 10^22 kg rmoon = 1.7374 x 10^6 m dearth to moon = 3.844 x 10^8 m (center to center) G = 6.67428 x 10^-11 N-m2/kg2 The minimum speed needed to reach the moon is vmin = 11068 m/s. If you leave the surface of the earth at this speed, how fast will you be moving at the surface of the moon? 2. Relevant equations Fgrav=G*m1*m2/r^2 PE earth=PE moon + KE moon ?? PE total = -GMe*m/ D-Re - GMm*m/D-Rm where D is the distance between centers of earth and moon, m is the mass of the person, Mm is the mass of the moon, and Me is the mass of the earth 3. The attempt at a solution The velocity cannot be zero at the surface of the moon. Although there is a point along the way that your speed approaches zero, as the spaceship falls to the moon it speeds up.