(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Triple integral of 1+z inside the cone z=2sqrt(x^2+y^2) above the xy plane and

bounded by z=6

2. Relevant equations

3. The attempt at a solution

when z=6, 6=2sqrt(r^2) so r=3 limits of integration are

z=6 to z=2r r=3 to r=-3 theta=2pi to theta=0

Just want to make sure my limits are right. Thanks!

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# Homework Help: Triple integral under a cone

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