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evilpostingmong
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Homework Statement
Triple integral of 1+z inside the cone z=2sqrt(x^2+y^2) above the xy plane and
bounded by z=6
Homework Equations
The Attempt at a Solution
when z=6, 6=2sqrt(r^2) so r=3 limits of integration are
z=6 to z=2r r=3 to r=-3 theta=2pi to theta=0
Just want to make sure my limits are right. Thanks!