Triple Integrals

  • Thread starter bodensee9
  • Start date
  • #1
178
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Homework Statement



Can someone see if I have set this up correctly? So I am to evaluate ∫∫∫6xydV. The region lies between z = 1+x+y and above the region in the xy plane bounded by the curves y = √x, y = 0, x = 1.
So, would this be equal to ∫∫∫6xydzdydx, where z is evaluated from 0 to 1+x+y, y is evaluated from √x to -1-x, and x is evaluated from 0 to 1? Thanks!!!


Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
144
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Your limits for z and x looks fine, but why do you think y goes from [itex]\sqrt{x}[/itex] to [itex]-x-1[/itex]? Where do you get that last mentioned limit for y?
 
  • #3
178
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I guess because that's where the projection of z = 1+x+y on the xy plane intersects the curve y = √x. so i thought y would range between √x and -1 - x. Thanks.
 

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