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Triple Integrals

  1. Jan 31, 2007 #1
    1. The problem statement, all variables and given/known data

    Can someone see if I have set this up correctly? So I am to evaluate ∫∫∫6xydV. The region lies between z = 1+x+y and above the region in the xy plane bounded by the curves y = √x, y = 0, x = 1.
    So, would this be equal to ∫∫∫6xydzdydx, where z is evaluated from 0 to 1+x+y, y is evaluated from √x to -1-x, and x is evaluated from 0 to 1? Thanks!!!

    2. Relevant equations

    3. The attempt at a solution
  2. jcsd
  3. Jan 31, 2007 #2
    Your limits for z and x looks fine, but why do you think y goes from [itex]\sqrt{x}[/itex] to [itex]-x-1[/itex]? Where do you get that last mentioned limit for y?
  4. Jan 31, 2007 #3
    I guess because that's where the projection of z = 1+x+y on the xy plane intersects the curve y = √x. so i thought y would range between √x and -1 - x. Thanks.
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