- #1
Icebreaker
From Shaum's: Compute the triple integral of [tex]f(r,\theta ,z)=r^2[/tex] over the region [tex]R[/tex] bounded by the paraboloid [tex]r^2=9-z[/tex] and the plane [tex]z=0[/tex]
This has me stumped. The volume bounded by [tex]r^2=9-z[/tex] and [tex]z=0[/tex] is not closed in 3-space. But if they really meant region, triple-integrating a region with no volume gives 0. What should I do?
This has me stumped. The volume bounded by [tex]r^2=9-z[/tex] and [tex]z=0[/tex] is not closed in 3-space. But if they really meant region, triple-integrating a region with no volume gives 0. What should I do?