A certain triple-star system consists of two stars, each of mass m = 7.00×1024kg, revolving about a central star of mass M = 1.69×1030kg in the same circular orbit of radius r = 2.00×1011m(see the figure). The two stars are always at opposite ends of a diameter of the circular orbit. What is the period of revolution of the stars in years(yr)?
The Attempt at a Solution
I know that the equation for period of motion is
T=2*pi*r^3/2 / sqrt (GM)
I'm just not sure if I can plug in values where M is the aggregate of masses M1 and M2..
Last edited by a moderator: