- #1

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- 37

- Homework Statement
- An ant walks on a piece of graph paper straight along the x axis a distance of 10.0 cm in 2.00 s. It then turns left 30.0° and walks in a straight line another 10.0 cm in 1.80 s. Finally, it turns another 70.0° to the left and walks another 10.0 cm in 1.55 s. Determine (a) the x and y components of the ant’s average velocity, and (b) its magnitude and direction.

- Relevant Equations
- N/A

I am having trouble with finding the x and y components of V3 . According to various different websites the correct way to find the components of V3 is

Vx=10*cos(100) and Vy=10*sin(100). I can see where the 100 comes from, the previous vector was already traveling 30 degrees and now V3 swung out an additional 70 degrees.

The way the angle is in this triangle i sketched for V3, the opposite side of this angle presents the length of the x component. The opposite side is traveling in the X axis. Likewise, from this angle the adjacent side is traveling up which in opinion is the length of the y component.

So from my perspective to find the x and y component I should solve for

Vx=10*Sin(100) and Vy=10Cos(100).

But this answer doesn't match up with other answers.

Could some help me understand if and why I am viewing this wrong?

Work is attached in PDF

Vx=10*cos(100) and Vy=10*sin(100). I can see where the 100 comes from, the previous vector was already traveling 30 degrees and now V3 swung out an additional 70 degrees.

The way the angle is in this triangle i sketched for V3, the opposite side of this angle presents the length of the x component. The opposite side is traveling in the X axis. Likewise, from this angle the adjacent side is traveling up which in opinion is the length of the y component.

So from my perspective to find the x and y component I should solve for

Vx=10*Sin(100) and Vy=10Cos(100).

But this answer doesn't match up with other answers.

Could some help me understand if and why I am viewing this wrong?

Work is attached in PDF