Trouble taking a derivative

  • Thread starter PhizKid
  • Start date
  • #1
PhizKid
477
1

Homework Statement


Derivative of [tex]\frac{y - 1}{y^2 - y + 1}[/tex]


Homework Equations





The Attempt at a Solution


d9DY1.png


The solution is [tex]\frac{y^2 - 2y}{(y^2 - y + 1)^2}[/tex] but in my work, the answer will have something to the 4th power on the top which will be impossible to cancel out. What have I done wrong?

Edit: Never mind, I see my mistake
 
Last edited:

Answers and Replies

  • #2
Scootertaj
97
0
Remember: [tex]\frac{d}{dx}\frac{f(x)}{g(x)} = \frac{g(x)f'(x) - f(x)g'(x)}{g(x)^2}[/tex]
 
  • #3
PhizKid
477
1
Yes but I don't like to work with the quotient rule. I should be getting the same answer using the product rule anyway, right?

Edit: Never mind, I see my mistake
 
  • #4
Scootertaj
97
0
That's fine.

Then, remember: [tex]-(y^2-y+1)^{-2} = -\frac{1}{(y^2-y+1)^2}[/tex]
(An expression to the -2 power doesn't equal 1/sqrt(expression))
 

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