1. The problem statement, all variables and given/known data Vector A = 3.5i + 1.8j and vector B = 1.7i + 4.8j . Find the components of A x B: 2. Relevant equations AxB = AB sin(theta) 3. The attempt at a solution Since vector A=3.5i+1.8j and B=1.7i+4.8j, I translated that into vectors. So, A is 3.94 @ 27.77*, and B is 5.09 @ 70.56*. This means that the angle between A and B is 42.79*. Using the AxB formula, I have 13.62. However, the problem (it's on WebAssign) wants the i, j, and k components. I tried the AxB formula with the individual i and j components, and I got 4.04 for the i direction, and 5.87 for the j direction. However, they're both wrong, and I have no idea how to find out the k direction... Help! Thanks in advance, -Angel.