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A balloon is placed in a pouch attached to the hose, which is then stretched through the width of the room. Assume that the strecthing of the hose obeys hooke's law with a spring constant 102 N/m. if the hose is stretched by 5.30m and then released, how much work does the force from the hose do on the baloon in the puch by the time the hose reaches its relaxed lenghty

The answer:

this is how i tried to solve it...F=-kx according to hooke's law..so i did -(102)(5.30)= -540.6 N ..and work is W=Fd..so i mulitiped the force with distance 5.30 and got -2865.18 which is not the answer...what am i doing wrong? thanks

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# Homework Help: Trouble with hooks law

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