- #1
fireman2020
- 4
- 1
Problem:
Attempted Solution:
The answer is actually (1/3)As^3+(1/2)Bs^2
Attempted Solution:
The answer is actually (1/3)As^3+(1/2)Bs^2
Daniel Gallimore said:Firstly, well done noting that the force on the cart and the displacement of the cart point in opposite directions.
Secondly, your bounds should not be from zero to [itex]-s[/itex] but from zero to [itex]s[/itex]. This is because [itex]s[/itex] represents a displacement from equilibrium, not a particular point on the ruler. It is not important that you traveled from a specific location [itex]x_1[/itex] to [itex]x_2[/itex]. Rather, this equation wants you to input the distance [itex]s[/itex] that was traveled.
Spring force is the force exerted by a compressed or stretched spring. It is a type of elastic force that is proportional to the amount of displacement of the spring from its equilibrium position.
Spring force can either push or pull an object depending on whether the spring is compressed or stretched. It can also cause the object to vibrate if the spring is attached to a moving object.
The strength of spring force is affected by the stiffness of the spring, the distance the spring is compressed or stretched, and the mass of the object attached to the spring.
If an object experiences too much spring force, the spring can become permanently deformed or even break. The object can also be pushed or pulled beyond its safe limits, resulting in damage or injury.
Spring force can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the distance it is compressed or stretched from its equilibrium position. The equation is F = -kx, where F is the force, k is the spring constant, and x is the displacement of the spring.