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[tex]\lim_{n \rightarrow \infty} 2^n \arcsin \frac{k}{2^n u_{n}} \text{, where \emph{k} is constant.}[/tex]

I'm given that [itex]\lim u_{n} = u[/itex], where u is constant.

Apparently the book says the answer is [itex]\frac{k}{u}[/itex], but I can't figure out why.