Either way is fine. Either way you prefer.raymanmusic said:Do I only draw member CDE, or do I draw EFG and CDE, and then solve sum of moments about joint C equal to zero?
The weight of the motor is given as 125kg in the problem. In order to calculate the weight, we can use the formula W = mg, where W is the weight, m is the mass, and g is the acceleration due to gravity. In this case, the weight of the motor is simply 125kg multiplied by the acceleration due to gravity (9.8 m/s^2), giving us a weight of 1225 N.
The maximum force that the crane needs to exert is equal to the weight of the motor, which we calculated to be 1225 N. This is because according to Newton's Second Law, the force required to accelerate an object (in this case, the motor) is equal to its mass multiplied by its acceleration, which in this case is just the acceleration due to gravity.
In order to calculate the tension in the crane's cables, we need to consider the forces acting on the motor. These include the weight of the motor (1225 N) and the tension in the cables. By using the principle of equilibrium, we can equate the sum of these forces to zero, and solve for the tension. This will give us the tension in the crane's cables while lifting the motor.
Aside from the weight of the motor, other factors that should be considered when calculating the member forces of the crane include the length and strength of the crane's arms, the angle at which the motor is being lifted, and any external forces such as wind or uneven terrain that may affect the stability of the crane.
To ensure the safety and stability of the crane, it is important to properly calculate and distribute the forces on the crane's members. This can be achieved by using appropriate materials and construction techniques, as well as regularly inspecting and maintaining the crane. It is also crucial to follow proper safety protocols and guidelines while operating the crane, and to take into account any external factors that may affect its stability.