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Truth table with Xor and T

  1. Nov 11, 2015 #1
    (( X xor Y ) xor Z ) xor T

    I hope the truth table is correct. I'm not sure, because of the T. T is always 1, right?

    X Y Z - (( X xor Y ) xor Z ) xor T

    111 - 0
    110 - 1
    101 - 1
    100 - 0
    011 - 1
    010 - 0
    001 - 0
    000 - 1
  2. jcsd
  3. Nov 11, 2015 #2


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    I cannot fathom what T is or why you say it is always 1. Given the assumption that it is, then your solution is correct but you need to explain why T is always 1. You do not show it in your work.

    And by the way, you are supposed to show your work, not just your final answer, else if you have something wrong how would we have any idea where you made a mistake?
  4. Nov 11, 2015 #3


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    T is always T (True), so: yes -- provided 1 is True in your 'system'.
    I don't think I can improve on your table :wink:
  5. Nov 11, 2015 #4


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    Ah. "T" for "True". I thought it was just another variable. Good catch. It's early. I'm still asleep. That's my story and I'm sticking with it. :smile:
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