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If A(t) = t i - t^{2} j + (t - 1) k and B(t) = 2t^{2} i + 6t k, evaluate (a) [tex]\int^{2}_{0}A \cdot Bdt ,[/tex] (b) [tex]\int^{2}_{0}A \times B dt.[/tex]
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Integral of t = t^{2}/2 = 21. If A (t) = t i - t^{2}j + (t -1) k, evaluate (b) [tex]\int^{2}_{0} A [/tex]
Sorry for giving a wrong problem....Integral of t = t^{2}/2 = 2
Integral of t^{2} = t^{3}/3 = 8/3
Integral of (t-1)=t^{2}/2 - t = 0
Net result 2i -(8/3)j
You need to show an attempt at solving the problem before receiving help!If A(t) = t i - t^{2} j + (t - 1) k and B(t) = 2t^{2} i + 6t k, evaluate (a) [tex]\int^{2}_{0}A \cdot Bdt ,[/tex] (b) [tex]\int^{2}_{0}A \times B dt.[/tex]
Yeah.... That's the process I've made... Then I integrate them with respect to t and evaluate from 0 to 2Moderator's note: thread moved from "Calculus & Analysis"
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You need to show an attempt at solving the problem before receiving help!
Start by evaluating A·B and AxB.