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Homework Help: Try this Vector Integration

  1. Mar 13, 2010 #1
    If A(t) = t i - t2 j + (t - 1) k and B(t) = 2t2 i + 6t k, evaluate (a) [tex]\int^{2}_{0}A \cdot Bdt ,[/tex] (b) [tex]\int^{2}_{0}A \times B dt.[/tex]
     
    Last edited: Mar 13, 2010
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  3. Mar 13, 2010 #2

    arildno

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    I have no idea!

    Can you help me out, by SHOWING WHAT YOU HAVE DONE SO FAR?
     
  4. Mar 13, 2010 #3

    mathman

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    Integral of t = t2/2 = 2
    Integral of t2 = t3/3 = 8/3
    Integral of (t-1)=t2/2 - t = 0

    Net result 2i -(8/3)j
     
  5. Mar 13, 2010 #4
    Sorry for giving a wrong problem....
     
  6. Mar 14, 2010 #5

    Redbelly98

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    Moderator's note: thread moved from "Calculus & Analysis"

    Homework assignments or any textbook style exercises are to be posted in the appropriate forum in our https://www.physicsforums.com/forumdisplay.php?f=152" area. This should be done whether the problem is part of one's assigned coursework or just independent study.


    You need to show an attempt at solving the problem before receiving help!

    Start by evaluating A·B and AxB.
     
    Last edited by a moderator: Apr 24, 2017
  7. Mar 14, 2010 #6
    Yeah.... That's the process I've made... Then I integrate them with respect to t and evaluate from 0 to 2
     
    Last edited by a moderator: Apr 24, 2017
  8. Mar 14, 2010 #7
    For the dot product of A and B, I obtained 2*t3+6*t2-6*t. Then integrate that from 0 to 2.

    For the cross product, I obtained -6*t3i+(2*t3-8*t2)j+2*t4k.
     
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