Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Try this Vector Integration

  1. Mar 13, 2010 #1
    If A(t) = t i - t2 j + (t - 1) k and B(t) = 2t2 i + 6t k, evaluate (a) [tex]\int^{2}_{0}A \cdot Bdt ,[/tex] (b) [tex]\int^{2}_{0}A \times B dt.[/tex]
    Last edited: Mar 13, 2010
  2. jcsd
  3. Mar 13, 2010 #2


    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    Dearly Missed

    I have no idea!

    Can you help me out, by SHOWING WHAT YOU HAVE DONE SO FAR?
  4. Mar 13, 2010 #3


    User Avatar
    Science Advisor

    Integral of t = t2/2 = 2
    Integral of t2 = t3/3 = 8/3
    Integral of (t-1)=t2/2 - t = 0

    Net result 2i -(8/3)j
  5. Mar 13, 2010 #4
    Sorry for giving a wrong problem....
  6. Mar 14, 2010 #5


    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper

    Moderator's note: thread moved from "Calculus & Analysis"

    Homework assignments or any textbook style exercises are to be posted in the appropriate forum in our https://www.physicsforums.com/forumdisplay.php?f=152" area. This should be done whether the problem is part of one's assigned coursework or just independent study.

    You need to show an attempt at solving the problem before receiving help!

    Start by evaluating A·B and AxB.
    Last edited by a moderator: Apr 24, 2017
  7. Mar 14, 2010 #6
    Yeah.... That's the process I've made... Then I integrate them with respect to t and evaluate from 0 to 2
    Last edited by a moderator: Apr 24, 2017
  8. Mar 14, 2010 #7
    For the dot product of A and B, I obtained 2*t3+6*t2-6*t. Then integrate that from 0 to 2.

    For the cross product, I obtained -6*t3i+(2*t3-8*t2)j+2*t4k.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook