# Try this Vector Integration

1. Mar 13, 2010

### yusukered07

If A(t) = t i - t2 j + (t - 1) k and B(t) = 2t2 i + 6t k, evaluate (a) $$\int^{2}_{0}A \cdot Bdt ,$$ (b) $$\int^{2}_{0}A \times B dt.$$

Last edited: Mar 13, 2010
2. Mar 13, 2010

### arildno

I have no idea!

Can you help me out, by SHOWING WHAT YOU HAVE DONE SO FAR?

3. Mar 13, 2010

### mathman

Integral of t = t2/2 = 2
Integral of t2 = t3/3 = 8/3
Integral of (t-1)=t2/2 - t = 0

Net result 2i -(8/3)j

4. Mar 13, 2010

### yusukered07

Sorry for giving a wrong problem....

5. Mar 14, 2010

### Redbelly98

Staff Emeritus
Moderator's note: thread moved from "Calculus & Analysis"

Homework assignments or any textbook style exercises are to be posted in the appropriate forum in our https://www.physicsforums.com/forumdisplay.php?f=152" area. This should be done whether the problem is part of one's assigned coursework or just independent study.

You need to show an attempt at solving the problem before receiving help!

Start by evaluating A·B and AxB.

Last edited by a moderator: Apr 24, 2017
6. Mar 14, 2010

### yusukered07

Yeah.... That's the process I've made... Then I integrate them with respect to t and evaluate from 0 to 2

Last edited by a moderator: Apr 24, 2017
7. Mar 14, 2010

### Dustinsfl

For the dot product of A and B, I obtained 2*t3+6*t2-6*t. Then integrate that from 0 to 2.

For the cross product, I obtained -6*t3i+(2*t3-8*t2)j+2*t4k.