Calculating Velocity: Moon Around Earth & Clocks in Burj Khalifa

In summary: The clocks on top would only be running 1.37 picoseconds faster than the Earth's center after 1 hour, whereas the velocity difference due to gravitational time dilation is 4.33192 picoseconds.
  • #1
Anakin Delabelle
2
0
Sometimes I get so bored that I just try to calculate certain experiments I've heard without know the solution. Like using the basic formula to calculate the speed of the moon around the Earth. This time I tried to calculate the differences between 2 clocks, on put on the highest building in the world (Burj Khalifa) with 828m of the ground and one in its basement so 0m.

First of all, I went searching for some variables I need to use :
  • Rotation of the Earth = 23h 59min 04s = 86164 s
  • Radius of Earth = 6378 x 103 m
  • Speed of light = 299 792 458 m/s

I also found the formula I needed to use :


cd0ef0ab32cb75d24e1baca01106d02f0d0ae0bd


d047edd48fc8cbe8c6277b0115d66be121e46ed9

To find the Velocity, I used the simple formula
b5edc54db08559dc3e33cb3cc568126e12b46521
and
e463711972f03d38362b2a4f330ed8a9d4b172b9


So, I'm trying to find the velocity of those 2 clocks relative to the center of the earth. And because one clock is further (as we see in the formula, if the angular speed is constant) it would have a faster velocity so it should go faster in time.

Velocity clock basement :

gif.latex?v_%7B1%7D%3D%5Cfrac%7B2.%5Cpi%7D%7B86164s%7D%20.6378.10%5E3m%20%3D%20465.gif


Velocity clock on top :

f.latex?v_%7B2%7D%3D%5Cfrac%7B2.%5Cpi%7D%7B86164s%7D%20.%286378.10%5E3m+828m%29%20%3D%20465.gif


Then I chose for a timeframe of an hour = 3600s

That means I need to calculate the space they have done with their velocity :

gif.latex?x_%7B1%7D%3D%20465.0916379%5Cfrac%7Bm%7D%7Bs%7D.3600s%3D1674329.gif


gif.latex?x_%7B2%7D%3D%20465.1520167%5Cfrac%7Bm%7D%7Bs%7D.3600s%3D1674547.gif
Now we should have all the variables for the formula I first mentioned, so let's fill it in :D

For the clock in the basement :

5Cfrac%7Bm%7D%7Bs%7D%7D%7B%5Cleft%20%28%20299792458%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%20%29%5E2%7D.gif
gif.latex?3599%2C9999999956680s%20%3D%203600s%20-%204%2C33192.gif


So 4.33192 nanoseconds faster than the center of the earth.
Now for the clock on top :

5Cfrac%7Bm%7D%7Bs%7D%7D%7B%5Cleft%20%28%20299792458%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%20%29%5E2%7D.gif
gif.latex?3599%2C9999999956667s%20%3D%203600s%20-%204%2C33329.gif


So 4.33329 nanoseconds faster than the center of the earth.There seems to be a theoretical a difference of 1.37 picoseconds after 1h on the clocks.

First of all, this is my first time trying to solve such a question, I just graduated high school. But I'm really interested in this field of physics.

If I made a mistake somewhere I would love to hear it, also English grammar mistakes will be visible, my apologize for those also.

Have a great day further.
 

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    gif.latex?v_%7B1%7D%3D%5Cfrac%7B2.%5Cpi%7D%7B86164s%7D%20.6378.10%5E3m%20%3D%20465.gif
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    f.latex?v_%7B2%7D%3D%5Cfrac%7B2.%5Cpi%7D%7B86164s%7D%20.%286378.10%5E3m+828m%29%20%3D%20465.gif
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    5Cfrac%7Bm%7D%7Bs%7D%7D%7B%5Cleft%20%28%20299792458%5Cfrac%7Bm%7D%7Bs%7D%20%5Cright%20%29%5E2%7D.gif
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  • #2
Anakin Delabelle said:
I also found the formula I needed to use :


cd0ef0ab32cb75d24e1baca01106d02f0d0ae0bd


d047edd48fc8cbe8c6277b0115d66be121e46ed9

The first formula relates the time of an event in two reference frames related by the Lorentz Transformation for a relative velocity ##v## in the x-direction, and isn't relevant here.

The second formula, for the gamma factor, is relevant here.

Note you you may also want to take gravitational time dilation into account. See:

https://en.wikipedia.org/wiki/Gravitational_time_dilation

Note also that "moving clocks run slow" in your reference frame.

You may also be interested in the famous Hafele-Keating experiment:

https://en.wikipedia.org/wiki/Hafele–Keating_experiment
 
  • #3
Oh well, I've still got a lot to learn, but thanks for the referrals, I'll try to understand them :)
 
  • #4
Anakin Delabelle said:
Oh well, I've still got a lot to learn, but thanks for the referrals, I'll try to understand them :)

I think gravitational time dilation is by far the greater factor in this case.
 

What is the formula for calculating velocity?

The formula for calculating velocity is v = d/t, where v is velocity, d is distance, and t is time.

How is velocity calculated for the moon orbiting the Earth?

The velocity of the moon orbiting the Earth can be calculated using the formula v = 2πr/T, where v is velocity, r is the radius of the moon's orbit, and T is the time it takes for the moon to complete one orbit.

How does the velocity of the moon change as it orbits the Earth?

The velocity of the moon remains constant as it orbits the Earth, following the laws of inertia and gravity.

What is the significance of calculating the velocity of the moon?

Calculating the velocity of the moon helps us understand the moon's orbit and its relationship with the Earth, and can also be used for predicting future positions of the moon.

How is velocity calculated for clocks in the Burj Khalifa?

The velocity of clocks in the Burj Khalifa can be calculated using the formula v = d/t, where v is velocity, d is the height of the building, and t is the time it takes for the clocks to move from the bottom to the top of the building.

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