- #1

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asymptotes horizontal and vertical

f(x)= 2x+3/x+2

f(x)=5x/x^2+1

f(x)= 2x+3/x+2

f(x)=5x/x^2+1

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- Thread starter poohbear1986
- Start date

- #1

- 20

- 0

asymptotes horizontal and vertical

f(x)= 2x+3/x+2

f(x)=5x/x^2+1

f(x)= 2x+3/x+2

f(x)=5x/x^2+1

- #2

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- 0

What values of x makes denominator zero? Do you have to ignore anything?

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- #3

HallsofIvy

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What you wrote is f(x)= 2x+(3/x)+ 2 and f(x)=(x/x^2)+ 1 but what you really MEANT was f(x)= (2x+ 3)/(x+ 2) and f(x)= x/(x^2+ 1).

How to do them? Start by looking up the definitions of horizotal asymptote and vertical asymptote.

- #4

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- 0

or

do you mean f(x) = (2x + 3)/(x + 2) and f(x) = 5x/(x^2 + 1)

Please clarify....

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