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Trying to figure out how to do these

  1. Nov 2, 2007 #1
    asymptotes horizontal and vertical

    f(x)= 2x+3/x+2


    f(x)=5x/x^2+1
     
  2. jcsd
  3. Nov 2, 2007 #2
    What values of x makes denominator zero? Do you have to ignore anything?
     
    Last edited: Nov 2, 2007
  4. Nov 3, 2007 #3

    HallsofIvy

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    In order to DO them right, first WRITE them right!

    What you wrote is f(x)= 2x+(3/x)+ 2 and f(x)=(x/x^2)+ 1 but what you really MEANT was f(x)= (2x+ 3)/(x+ 2) and f(x)= x/(x^2+ 1).

    How to do them? Start by looking up the definitions of horizotal asymptote and vertical asymptote.
     
  5. Nov 4, 2007 #4
    do you mean f(x) = 2x + (3/x) + 2 and f(x) = (5x/x^2) + 1

    or

    do you mean f(x) = (2x + 3)/(x + 2) and f(x) = 5x/(x^2 + 1)

    Please clarify....
     
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