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After bungee jumping off a bridge, a person begins to swing as a pendulum, the rope being 77 m long. The person's speed is 14 m/s as it passes through its lowest point. (a) find the height to which it rises above this position before stopping. (b) what angle does the pendulum then make with the vertical?

given:

L = 77 m

Vmax = 14 m/s

T (period of pendulum) = 2 * pi* squareRoot(L / g)

T = 2 * pi * squareRoot(77 m / 9.8 m/s^2)

T = 17.6 s

Avg Velocity = (Vf - Vi) / 2

= (14 m/s - 0) /2

= 7 m/s

dt = avg Velocity * t

= 7 m/s (17.65 s)

= 1232 m

d = dt / 4

d = 30.8 m

My problem is finding the angle. because the distance is not straight line so there cannot be a right triangle. I have absolutely no idea what to do here. Am I right on the first part. I divided dt by 4 because there is 4 parts to the period of a pendulum. At least I think thats right.

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# Trying to find an angle

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