Here it goes: After bungee jumping off a bridge, a person begins to swing as a pendulum, the rope being 77 m long. The person's speed is 14 m/s as it passes through its lowest point. (a) find the height to which it rises above this position before stopping. (b) what angle does the pendulum then make with the vertical? given: L = 77 m Vmax = 14 m/s T (period of pendulum) = 2 * pi* squareRoot(L / g) T = 2 * pi * squareRoot(77 m / 9.8 m/s^2) T = 17.6 s Avg Velocity = (Vf - Vi) / 2 = (14 m/s - 0) /2 = 7 m/s dt = avg Velocity * t = 7 m/s (17.65 s) = 1232 m d = dt / 4 d = 30.8 m My problem is finding the angle. because the distance is not straight line so there cannot be a right triangle. I have absolutely no idea what to do here. Am I right on the first part. I divided dt by 4 because there is 4 parts to the period of a pendulum. At least I think thats right.