I'm trying to the follow the work shown in the textbook, but getting a little confused.(adsbygoogle = window.adsbygoogle || []).push({});

Theorem I.Suppose the function f(x,y) is defined in some neighborhood of the of the point (a,b). Suppose one of the partial derivatives, say, ∂f/∂x, exists at each point of the neighborhood and is continuous at (a,b), while the other partial derivative is defined at least at the point (a,b). Then f is differentiable at (a,b).

The first thing the book does is write down

f(a+h, b+k) - f(a,b) = f(a+h, b+k) - f(a, b+k) + f(a, b+k) - f(a,b).

Okay. So far, so good.

Now, the part I put in red looks like the [f(a,b+k)-f(a,b)]/k, the partial derivative of f with respect to y at (a,b) when k approaches zero. But since k is just k, we can write this as

f(a+h, b+k) - f(a, b+k) = k ∂f/∂y|_{(a,b)}+ Ω_{1}k, where Ω_{1}approaches zero as k approaches 0.

The part I put in blue, I suppose, could similarly be rewritten as h ∂f/∂x|_{(a,b+k)}+ hΩ_{2}. Instead the book uses the mean value theorem as such:

f(a+h, b+k) - f(a, b+k) = h ∂f/∂x|_{(a+øh, b+k)}, where 0<ø<1.

Because ∂f/∂x is assumed to be continuous at (a,b), we can write

∂f/∂x|_{(a+øh, b+k)}= ∂f/∂x|_{(a,b)}+ Ω_{2}, where Ω_{2}--> 0 as k --> 0 and h --> 0.

The part in green is what I do not understand. Please explain.

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# Homework Help: Trying to prove something

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