Trying to understand FCNCs

  1. Hi, I'm trying to understand the process in the Feynman diagram below:

    [​IMG][/IMG]

    Specifically I'm wondering if the virtual quark has to emit a photon / Z boson and if so why? Also I don't understand how the photon / Z boson decays to a di-lepton pair since surely this violates spin conservation given that the photon / Z boson has spin 1 and the di-lepton pair will have opposite spins cancelling each other out.

    I'd much appreciate any help :)
     
  2. jcsd
  3. Hepth

    Hepth 501
    Gold Member

    You can have an external lepton flip spin states, so that they add to what the decaying particle is (spin 0 or 1), in order to conserve angular momentum. But this will give you an extra factor of lepton mass. Its called "Helicity Suppression".

    As for "has to emit a photon / Z boson", what else would it emit to get the in state to the out state? Actually I think you could also draw a box diagram:

    Code (Text):

    b--o--c--o--s
       |     |  
       W     W
       |     |
    e--o-nu--o--e
    as well as the one where the gamma/Z comes off of the W in the loop, though these contribute less I believe.
     
  4. Ah okay I'll look into that. When you say "what else would it emit to get the in state to the out state?" do you mean what else would it emit to have a di-lepton pair in the final state? Because what I'm asking is does there have have to be a photon or di-lepton pair in the final state or is a decay like Lambda_b -> pK possible without emiting a photon?

    Thank you for the response!
     
  5. Hepth

    Hepth 501
    Gold Member

    ##\Lambda_b \rightarrow p K^{-}## is possible alone, and has been measured :

    http://pdg.lbl.gov/2013/listings/rpp2013-list-lambdab-zero.pdf

    Scroll down to ##\Gamma_{20}##
     
  6. Ah >__< okay thank you for the help :)
     
  7. Hepth

    Hepth 501
    Gold Member

    But also remember without the muon pair the leading diagram to the decal L->pK is NOT a FCNC with a loop. It would be the W emission diagram, where
    Code (Text):

    u-----u
    d-----d
    b--w--u

    w---> (s ubar)
     
    This will be proportional to Gf Vub Vus, where the FCNC one is a sum over the up-types in the loop, so Vub Vus , Vcb Vcs, Vtb Vts, times the loop factors, and an extra alpha_EM.
     
  8. That's interesting, according to the pdg its branching fraction is still of the same order as the FCNC decay modes which occur at the one-loop level. Surely if it occurs at the tree level it should have a higher branching fraction?
     
  9. massive particles can be both in RH and LH states (because their LH and RH components are coupled through higg's vev)... only the neutrinos which are considered massless the antiparticle and particle exist in one or the other (the coupling to the higgs vev is very weak)...
    Am I wrong?
     
  10. Not nessecarily. The tree level mode [itex]\Lambda_{b}->p^{+}k^{-}\mu^{+}\mu^{-}[/itex] is supressed by the small CKM element [itex]V_{bu}[/itex] Where the FCNC is a b->s transition which is only moderatley supressed due to the large top yukawa.

    Moreover, this FCNC decay doesn't have helicity supression. Helicity supression happens when a scalar decays to light fermions through a vector coupling, like the decay [itex]B_{s}->\mu^{+}\mu^{-}[/itex]
     
  11. Hepth

    Hepth 501
    Gold Member

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