Two boys play tug of war.If according to newton's third law, for every force a there is a reaction b with the same magnitude but opposite direction. What determines who wins?
Our professor gave a hint that it has something to do with the ground.
f=ma and newtons 3rd law
The Attempt at a Solution
I have identified these forces:
A= force exerted by boy1 to the rope
A'=reaction to A ,force exerted by the rope to boy1
B=force exerted by boy1 to the rope
B'=reaction to B ,force exerted by the rope to boy2
Fa=Friction exerted at boy1
Fb=Friction exerted at boy2
Our professor said that no one wins if the ground is frictionless but i cant see why.