A turbine is installed in a vertical pipe line, 150mm diameter. A gauge is connected to the pipe at a point A above the turbine and another at point B below the turbine, the vertical distance between A and B being 1.2m. When the discharge is 0.06m^3/s, the gauages read 400kN/m^3 and 35kN/m^3 respectively. Calculate the output power from the turbine, assuming it to be 85% efficient. I've found the Cross sectional area = 0.01767m^2 Vol per sec = 0.06 therefore 0.06 = m/roh 0.06 = m/10^3 therefore mass flow rate = 60 Q = AV 0.06 = 0.01767V therefore V = 3.395m/s Then gone on to use Bernoulli's ... unsucessfully! Any help? Am I on the right tracks or?