- #1

- 50

- 0

(mass(b1) * 9.81 * sin 30) + (mass(b2) * 9.81 * .145) = T

to find the tension which equals 44.09 which is not the answer. I can find the acceleration once i get the tension i believe by f=ma.

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- Thread starter ViewtifulBeau
- Start date

- #1

- 50

- 0

(mass(b1) * 9.81 * sin 30) + (mass(b2) * 9.81 * .145) = T

to find the tension which equals 44.09 which is not the answer. I can find the acceleration once i get the tension i believe by f=ma.

- #2

Doc Al

Mentor

- 45,261

- 1,616

- #3

- 50

- 0

i tried F=ma and i got 22.045 N and it still doesn't work

- #4

Doc Al

Mentor

- 45,261

- 1,616

Did you do what I suggested? Apply F=ma to each block separately. You'll get two equations.

- #5

- 50

- 0

(U*g*m(2) + m(1)*g* sin(theta))/2 = T

so it was (1.7638 + 42.37) /2 = 22.04 = T

but it is not right

- #6

Doc Al

Mentor

- 45,261

- 1,616

(a) Identify the forces on m1; Apply F = ma to m1.

(b) Identify the forces on m2; Apply F = ma to m2.

You'll get two equations. Do this.

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