A cube with 1 kg mass is put on top of a bigger cube with 3kg mass and 1 meter edges.
If 10 N force is exerted on the bigger cube, while the maximum friction between the cube surface is 2 N, and g=10m/s^2 , then at one time the small cube will fall to the floor.
The time needed for the small cube to reach the floor since the force is exerted is about ...
(Assume there is no friction between the floor and the big cube)
A. 1 s
B. 1.4 s
C. 1.7 s
D. 2.4 s
E. 2.7 s
Newton's law of motions
The Attempt at a Solution
Free-body diagram for block A
A ----> F (friction between A and B) = 2N
Free-body diagram for block B
F(friction between A and B) = 2N <-------B --------> F = 10 N
Then, I get stuck..