How do the blocks of power have the same kinetic energy?

In summary, we have discussed the relationship between force, distance, and kinetic energy in the context of two blocks with equal mass and varying velocities. We concluded that since the same work is performed on both blocks, they have equal kinetic energy. We then determined that the smaller block moves at twice the speed of the larger block, and the distance pushed for the larger block is four times larger than that of the smaller block.
  • #1
soupastupid
34
0

Homework Statement



the force is given as F
the distance pushed is given as D


Homework Equations



W= F*d
F=ma
KE = 1/2 mv^2


The Attempt at a Solution



the blocks have the same kinetic energy
 

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  • #2
soupastupid said:
the blocks have the same kinetic energy
Correct. Since the same work (F*d) is performed, the resulting KE is the same.
 
  • #3
ok for part b it is asking how fast the lighter block is moving when compared to the big block.

im thinking

the F*D is the same

and KE is .5mv^2

and so

.5(4m)(v_L)^2 = .5m(v_S)^2

the m and .5 cancel out

so i have

4(V_L)^2=(V_S)^2

SQRT BOTH SIDE

and then

V_S = 2V_L

so therefore

the smaller box is moving twice as fast as the big box?

right?
 
  • #4
Perfect!
 
  • #5
ok

now both the blocks have the same speed
and now have the same V

ok...

and its asking for distance
so i have to find out how far each box is pushed

and
work of larger box =

W_L= F*D_L
W_S=F*D_S

KE_L = .5(4M)(v)^2
KE_S = .5(M)(v)^2

and since W=chainge in KE (KE_initial is 0)

F*D_L = .5(4M)(v)^2
(v)^2 = (F*D_L) / .5(4M)

F*D_S = .5(M)(v)^2
(v)^2 = (F*D_S)/.5(M)

(F*D_S)/.5(M) = (F*D_L) / .5(4M)

.5 M and F cancel out

D_S = (D_L) / 4
D_L = 4D_S

the distance the larger box has to be pushed is 4 times larger than that of the smaller box?
 

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  • #6
Exactly!
 

1. What is the concept of "Two blocks of power" in science?

The concept of "Two blocks of power" refers to the idea that energy can be transferred or transformed between two distinct objects or systems.

2. How is power measured in this scenario?

Power is measured in watts (W) which is equal to the amount of energy transferred or transformed per unit time.

3. What is the formula for calculating power?

The formula for calculating power is P = W/t, where P is power in watts, W is work in joules, and t is time in seconds.

4. How does the size or mass of the blocks affect the power transferred?

The size or mass of the blocks does not directly affect the power transferred. However, it may affect the amount of energy that can be stored in the blocks and thus, indirectly impact the power transferred.

5. Can the power transferred between the two blocks be increased?

Yes, the power transferred between the two blocks can be increased by either increasing the amount of energy stored in the blocks or decreasing the time it takes for the energy to be transferred or transformed.

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