1. The problem statement, all variables and given/known data Block A (mass 2.25 kg) rests on a tabletop. It is connected by a horizontal cord passing over a frictionless pulley to a hanging block B (mass 1.30 kg.) The coefficient of kinetic friction between block A and the table is 0.450. After the blocks are released from rest, find a. the speed of each block after moving 3.00 cm and b. the tension of the cord. 2. Relevant equations 3. The attempt at a solution Block A: Fgravity: (2.25kg)(9.8m/s2) = 22.05N Fnormal: 22.05N Ffriction: (22.05N)(0.450) = 9.92N Resultant force: 22.05N - 9.92N = 12.13N Block B: Fgravity: (1.30kg)(9.8m/s2) = 12.74N I have no idea what to do after this. I found the exact same problem through a search but I don't understand the explanation.