(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Block A (mass 2.25 kg) rests on a tabletop. It is connected by a horizontal cord passing over a frictionless pulley to a hanging block B (mass 1.30 kg.) The coefficient of kinetic friction between block A and the table is 0.450. After the blocks are released from rest, find a. the speed of each block after moving 3.00 cm and b. the tension of the cord.

2. Relevant equations

3. The attempt at a solution

Block A:

F_{gravity}: (2.25kg)(9.8m/s^{2}) = 22.05N

F_{normal}: 22.05N

F_{friction}: (22.05N)(0.450) = 9.92N

Resultant force: 22.05N - 9.92N = 12.13N

Block B:

F_{gravity}: (1.30kg)(9.8m/s^{2}) = 12.74N

I have no idea what to do after this. I found the exact same problem through a search but I don't understand the explanation.

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# Homework Help: Two blocks on a tabletop

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