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## Homework Statement

A 0.5kg wooden block is placed on top of a 1.0kg block. The coefficient of static friction between the two blocks is 0.35. The coefficient of kinetic friction between the lower block and the level table is 0.20. What is the maximum horizontal force that can be applied to the lower block without the upper block slipping?

## Homework Equations

F

_{NET}= ma = 0

## The Attempt at a Solution

F

_{K}= 1.5 * 9.8 * 0.20

F

_{K}= 2.94 N

F

_{S}= 0.5 * 9.8 * 0.35

F

_{S}= 1.715

F

_{NET}= F

_{S}= F

_{A}- F

_{FK}

1.715 N = F

_{A}- 2.95 N

1.715 N + 2.95 N = F

_{A}

4.655 N = F

_{A}

4.7 N = F

_{A}

Therefore, the maximum horizontal force that can be applied is 4.7 N without the upper, 0.5 kg, block moving.

Is this correct?