Two capacitor problem

Brentski,

It seems to me that the capacitance values you got are way too small. They should add up to something like .0545 F, and should add in inverse to .0126 F. Maybe I'm off by a factor of 2 pi, but even then my values are WAY larger than yours.

1KHz is a very low frequency. 10V is a low voltage. But 126mA is a huge current. It's going to take a big capacitor for that kind of current.

Carl

 

Seems like there are some formulas missing? Are you looking to include capacitive reactance? 1 over the square root of 2 pi fc ? (or something like that) . In your equation, what does 'w' represent?

What happens if you plug in a range of arbitrary cap values? then plot the results and approximate whether to increase/decrease values? Id try but dont know what 'w' refers to

 

Your expression for current is wrong. It should be: [itex]I = V/X_c = V/\omega C[/itex]

So for the series configuration:

[tex]I_s = V(1/C_1 + 1/C_2)/\omega[/tex]

and in parallel:

[tex]I_p = V/\omega(C_1 + C_2)[/tex]

Plug in values for the two currents and V and work out C₁ and C₂

AM