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1. The problem statement, all variables and given/known data

Two charges are located on a horizontal axis. The Coulomb constant is 8.98755x10^9 Nm^2/C^2.

a) Determine the electric field at p on a vertical axis as shown in the attachment. Up is the positive direction. Answer in units of V/m.

b) Calculate the vertical component of the electric force on a -3.1e-6C charge placed at point p. Answer in units of N

2. Relevant equations

a) E=kQ/r^2

b) F=Eq

3. The attempt at a solution

a) I'm fairly certain I know how to find the field strength from the two charged particles, if point p was directly on the field and in the center.

E=E1+E2

E=k/r^2(Q+q)

E=8.98755e9/3^2(2.2e-6+2.2e-6)

E=4393 V/m

But I think I also need to take into account that p isabovethe two particles, but now I'm stuck...

b) I think this part would be easier, I just can't do it since I haven't gotten the answer to part a.

F=Eq

F=E(that would be found in part a)(-3.1e-6)

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# Homework Help: Two charges create an electric field-electric field strenght at a point above h.fiel

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