(adsbygoogle = window.adsbygoogle || []).push({}); 1. Two charges are arranged on the x axis. q1 = +8.00 μC, and

q2 = +5.00 μC. a = 25.0 cm. q1 is held fixed and q2 is released from rest.

Both q1 and q2 have a mass of 20.0 g.

Calculate x2, the position of q2, when it reaches a speed of 8.00 m/s.

a is the distance between q1 and q2. q1 is at the origin and q2 is along the x axis at a distance "a"

2. Ek= 1/2mv^2

V = kq/r

3.

first i converted m to kg = 20 x 10^-3

Ek = 1/2mv^2

V = kq1/r + kq2/r

1/2mv^2 = kq1/r + kq2/r

1/2(20x10^-3)(8)^2 = k(8x10^-6)/x + k(5x10^-6)/(x-0.25)

solving for x gives me wrong answer

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# Homework Help: Two Charges Energy

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