Two concentric shells connected by a wire asap

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In summary, the conversation discusses the distribution of charge on two concentric shells made of conductive materials. The problem states that the ratio of the radius of the two shells is 6, and they are initially charged with a total of 100 nc. The question asks what the final charge on both shells would be after they are connected with a wire. The solution provided uses the formula Q1/Q2 = R1/R2, which is only valid for two far conducting shells connected with a wire. The conversation also mentions that all the charge should go to the outer shell, which is confirmed by the use of the formula. Therefore, the final charge on the shells would be 0 and 100 nc, respectively.
  • #1
Conductivity
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Homework Statement


The problem states:
2 concentric shells made out of conductive materials as in the diagram. R2/ R1 = 6. If the shells were charged with a total charge of 100 nc the connected with a wire, Then the final charge on both shells would be?
1) 33.3, 66.7 2) 30, 70 3) 20, 80 4) 50,50 5) 14.3,85.7

Homework Equations


Voltage at both end points of the wire should be the same

The Attempt at a Solution


Shouldn't all the charge go to the outer shell? So it will be 0, 100

The solution provided used this formula:
Q1/ Q2 = R1/R2
https://prnt.sc/jmp453

Where we only used this formula for the case of two really far conducting shells connected with a wire.

Exam tomorrow, Thank you in advance.
 
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  • #2
While I’m sure someone will respond, my suggestion is to seek out a fellow student and see if you both can work this out since you’re concerned about your exam and we may not answer in time.
 
  • #3
Conductivity said:
Shouldn't all the charge go to the outer shell?
It should. No potential difference between the two shells means no electric field. No field means no charge: a Gaussian volume, spherical, just inside the outer shell should not contain any charge.

Your answer is correct.
 
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What is the purpose of two concentric shells connected by a wire?

The purpose of connecting two concentric shells with a wire is to create a capacitor, which is a device used for storing electrical energy.

How does the capacitance of the two shells connected by a wire change with distance?

The capacitance of the two shells connected by a wire increases as the distance between the two shells decreases. This is because the electric field between the two shells becomes stronger as they get closer, resulting in a higher capacitance.

Can the capacitance of the two shells connected by a wire be changed by varying the length of the wire?

No, the capacitance of the two shells connected by a wire is determined by the distance between the shells and the material properties of the shells. The length of the connecting wire does not affect the capacitance.

What happens to the capacitance of the two shells connected by a wire if the wire is replaced with a longer wire?

The capacitance would not change if the wire is replaced with a longer wire, as long as the distance between the two shells remains the same. The capacitance is only affected by the distance between the shells, not the length of the connecting wire.

How does the capacitance of two concentric shells connected by a wire compare to the capacitance of two parallel plates?

The capacitance of two concentric shells connected by a wire is generally lower than the capacitance of two parallel plates with the same dimensions. This is because the electric field is more concentrated between the two parallel plates, resulting in a higher capacitance.

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