Two conducting infinite plates

  • Thread starter 1MileCrash
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The Attempt at a Solution



Shouldn't it be double this answer?
 

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  • #2
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Anyone? The charge density of both should be considered, and since they are the same, that is 2 times the given charge density divided by the permittivity constant.
 
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SammyS
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Anyone? The charge density of both should be considered, and since they are the same, that is 2 times the given charge density divided by the permittivity constant.
If you use Gauss's Law to find the electric field between the plates, your Gaussian surface will only enclose charge from one plate or the other.
 

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