JM2107
For a lens of focal length f, what value of the distance between the object and the lens[D0] would give an image with a magnification of one?

Is it possible to obtain a non-inverted image with a converging spherical lens? Explain please?

Any response would be greatly appreciated, and I would like to thank anyone for their response to this thread in advance.

Related Introductory Physics Homework Help News on Phys.org
Hi JM2107,
to answer questions like this, you could use use 2 methods:
1) Draw 3 rays, remembering that...
... focal ray becomes parallel ray
... parallel ray becomes focal ray
... central ray is not refracted
2) Use the Law of lenses: 1/o + 1/i = 1/f
where
o = distance of object from lens
i = distance of image from lens
f = focal length

Got it? Claude Bile
It is not possible to obtain a non inverted image using a single converging lens. It is therefore not possible to obtain a magnification of 1, though it is possible to obtain a magnification of -1. (Inverted images have a negative magnification by convention).

The reason for this is purely geometrical. Arcnets outlined a standard graphical method of seeing why this is.

Originally posted by Claude Bile
It is not possible to obtain a non inverted image using a single converging lens.
R u sure? How about a virtual image? See here...

Last edited by a moderator:

Yes, it is possible to obtain a non-inverted image with a converging lens. As long as the object is between the focal length point and the lens it is possible. Of course this would be a virtual image and the image would be magnified.

m=-d(image)/d(object)

If m=1 than we have an equation where we can put d (object) = - d (image). Since 1/f = 1/d (object) + 1/d (image) and since d (object) = - d (image), therefore 1/f = 0

So there is no distance that would give a magnification of one.