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Two Dimensional Force

  1. Oct 9, 2007 #1
    1. The problem statement, all variables and given/known data

    In a two-dimensional tug-of war, Alex, Betty, and Charles pull horizontally on an automobile
    tire. The angle between Alex and Betty is 137degrees. The tire remains
    stationary in spite of the three pulls. Alex pulls with a force of magnitude 220 N, and Charles
    pulls with a force of magnitude 170 N. Note that the direction of the force applied by Charles
    is not given. What is the magnitude of force with which Betty pulls?

    2. Relevant equations

    F1 + F2 + F3 = 0 ?

    3. The attempt at a solution

    I do not know how to even approach this problem. Charles could be pulling with Betty, or with Alex, or in some other random direction. What formula could I use that would compensate for Charles?
     
  2. jcsd
  3. Oct 9, 2007 #2

    Doc Al

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    Staff: Mentor

    Hint: What must be the magnitude of the sum of Alex's force + Betty's force?
     
  4. Oct 9, 2007 #3
    You are incredible.
    <3
     
  5. Oct 9, 2007 #4

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Set up a coordinate system. let's set it up so that Alex is pulling along the positive x-axis: his force vector is <220, 0>. Then Betty is pulling at an angle of 137 degrees has force vector <Bcos(137), Bsin(137)> where "B" is the magnitude of the force (which is what you are asked). Finally, we know that Charles is pulling with magnitude 170 but don't know the angle: let's call the angle [itex]\theta[/itex] degrees. His force vector is [itex]<170 cos(\theta),170 sin(\theta)>[/itex]. The total force vector is [itex]<220+ Bcos(137)+ 170cos(\theta), Bsin(137)+ 170sin(\theta>= <0, 0>[/itex]. That gives you two equations to solve for B and [itex]\theta[/itex].
     
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