Two-Dimensional Motion Problem

  • Thread starter scharry03
  • Start date
  • #1
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Homework Statement


A skier leaves the ramp of a ski jump with a velocity of 10.0 m/s, 15.0° above the horizontal, as shown in Figure P3.57. The slope is inclined at 50.0°, and air resistance is negligible. Find the distance from the ramp to where the jumper lands .
image092020141179.png



Homework Equations


tan50degrees=Yf/Xf
Yf = Yi + Vyi(t) + .5(ay)t2
Xf=Xi+Vx(t)


The Attempt at a Solution


Plugging in numbers into the first second equation using the first equation and solving for distances gave me the following: Xf(tan50) = 2.59t + -4.9t2 . Then I solved for the third equation and resulted in Xf=9.66t. Plugging this into the partially solved second equation yielded: 9.66tan(50)t = 2.59t - 4.9t2 which simplifies to -4.9t2 - 8.91t. t is supposed to equal 2.88 seconds but my solution doesn't yield that at all. What am I doing wrong? Thanks.
 

Answers and Replies

  • #2
12
1
got it... the Yf i used was not negative.
 

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