1. The problem statement, all variables and given/known data A stuntman must jump in a pool from a 50.0 meter tall building. The pool is a horizontal distance of 21.0 meters from the base of the building. a) What is the initial velocity of the stuntman to be able to land in the pool? b) Do you think this velocity is reasonable for a human? c) Realistically, how tall must this building be for the stuntman to be able to make the landing safely? 2. Relevant equations Vf^2 = Vi^2 + 2aΔx Vf = Vi + aΔt Xf-Xi = Δx Given: Xix = 0m Xfx = 21m Xiy = 50m Xfy = 0m Δx = 21m Δy = -50m a= -9.81m/s^2 Viγ = 0m/s Relevant Unknowns: Δt = ? Vfγ = ? 3. The attempt at a solution Vf^2 = Vi^2 + 2aΔx Vf^2 = 0^2 + 2(-9.81m/s^2)(-50m) Vf^2 = 2(9.81m/s^2)(50m) Vf^2 = 981 Vf = 31.3 m/s Vf = Vi + aΔt 31.3 = 0 + (-9.81m/s^2) Δt 31.3 = -9.81m/s^2 (Δt) 31.3 = Δt -9.81m/s^2 Yeah, you see the issue, I made a stupid mistake and my brain is on 0 hours of sleep. and I have school in 1 hour.