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## Homework Statement

A stuntman must jump in a pool from a 50.0 meter tall building. The pool is a horizontal distance of 21.0 meters from the base of the building.

a) What is the initial velocity of the stuntman to be able to land in the pool?

b) Do you think this velocity is reasonable for a human?

c) Realistically, how tall must this building be for the stuntman to be able to make the landing safely?

## Homework Equations

Vf^2 = Vi^2 + 2aΔx

Vf = Vi + aΔt

Xf-Xi = Δx

Given:

Xix = 0m

Xfx = 21m

Xiy = 50m

Xfy = 0m

Δx = 21m

Δy = -50m

a= -9.81m/s^2

Viγ = 0m/s

Relevant Unknowns:

Δt = ?

Vfγ = ?

## The Attempt at a Solution

Vf^2 = Vi^2 + 2aΔx

Vf^2 = 0^2 + 2(-9.81m/s^2)(-50m)

Vf^2 = 2(9.81m/s^2)(50m)

Vf^2 = 981

Vf = 31.3 m/s

Vf = Vi + aΔt

31.3 = 0 + (-9.81m/s^2) Δt

31.3 = -9.81m/s^2 (Δt)

__31.3__= Δt

-9.81m/s^2

Yeah, you see the issue, I made a stupid mistake and my brain is on 0 hours of sleep. and I have school in 1 hour.