- #1
gracy
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Homework Statement
four point charges are placed at the corners of a square as shown in the figure having side 10 cm.If q is 1μC then what will be electric field intensity at the centre of the square?
Homework Equations
3. The Attempt at a Solution [/B]
Half of diagonal
a/√2
0.1/√2
Electric field due to charge "q"
=9 ×10^9 ×1×10^-6/(0.1/√2 )^2=18×10^5
But the thing I m not getting is
In the solution it has been given that at center there are two electric field which are perpendicular to each other.I want to know how?