Force on Each Mass in a Two-Mass Spring System

In summary, the question asks about the force felt by two masses attached to opposite ends of a spring when the spring is stretched by X meters in opposite directions. The formula F=-kx is used to calculate the force, and in this case the answer is F=k*2x. This is because each mass is stretched by the same amount, so the total stretch of the spring is 2x. When applying the same force to both sides, the formula Fspring=kx is used but only for one of the applied forces. This is because the other side is keeping the spring from accelerating, according to Newton's third law. When compressing or stretching the spring by a certain amount, the total stretch from both ends is considered to
  • #1
Hereformore
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Homework Statement


Two masses attached to opposite ends of a spring. What is the Force felt by each mass if each mass is stretched by Xmeters in opposite directions away from each other.

Homework Equations


F=-kx

The Attempt at a Solution


So my book says the answer is F=k*2x.

Each mass has the same mass and is stretched from their equilibrium by the same amount X. so the spring is stretched a total amount of 2x.

So since the spring force is proportional to the displacement of the spring/stretch of the spring, it would make sense that the spring force would be F=k*2x since 2x is the total displacement.

But what I'm havin gtrouble understanding is how to distinguish between situations like this when the spring is stretched by the same amount on both sides and problems where the same force is applied to both sides.

When the same force is applied to both sides, you use the same formula Fspring = kx , but for the force applied you only consider one of the applied forces rather than both combined, on the notion that the other side is what's keeping the spring from accelerating, Newtons third law.

But when you actaully compress the spring or stretch it by a certain amount, even if you stretch it from both ends, you consider the total stretch added from both ends to consider the recoil force, am i right?

And lastly, (Thanks guys haha) is the reason why you don't consider both forces when you apply the same force to both sides that compression could only occur if there was a counter force? Because the lack of movement allows for the compression to occur? Does that make sense? its weird because it's like we're using the applied force twice,
once to cancel out the counter force from the other end of the spring (i.e. from a wall or from someone on the other end of the spring)and then again when determining the compression caused by said force.
 
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  • #2
I'm having a little trouble understanding your question. Can you give a specific example of the two situations you are referring to?

Chet
 
  • #3
A lot of people make the mistake of thinking that if there's force T pulling at each end then the tension is 2T. But in a static set-up, it is not possible to pull at one end only.
In the OP set-up, it might help to think of the spring as two (half-length) springs fixed at the centre. If you chop a spring of constant k in half then each half will have a constant 2k.
 

1. How does the mass affect the force in a two-mass spring system?

In a two-mass spring system, the force on each mass is directly proportional to the mass of the object. This means that the greater the mass of the object, the greater the force on that object.

2. What is the equation for calculating the force on each mass in a two-mass spring system?

The equation for calculating the force on each mass in a two-mass spring system is F = kx, where F represents the force, k is the spring constant, and x is the displacement of the mass from its equilibrium position.

3. Does the position of the masses affect the force in a two-mass spring system?

Yes, the position of the masses does affect the force in a two-mass spring system. The farther the mass is pulled from its equilibrium position, the greater the force acting on it.

4. How does the spring constant affect the force in a two-mass spring system?

The spring constant plays a crucial role in determining the force on each mass in a two-mass spring system. A higher spring constant results in a greater force, while a lower spring constant results in a smaller force.

5. Can the force on each mass be different in a two-mass spring system?

Yes, the force on each mass can be different in a two-mass spring system. This is because the force is directly proportional to the mass and the displacement of each mass from its equilibrium position, which can vary based on their individual characteristics.

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