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yxgao
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There is a diagram that accompanies it so if the explanation isn't clear you can refer to the sample test posted on
the GRE.org website.
83 on GRE. Consider a particle moving without friction on a rippled surface, as shown above. Gravity acts down in the negative h direction. The elevation h(x) of the
surface is given by h(x) = d cos[kx]. If the particle starts at x=0 with a speed v in the x direction, for what values of v will the particle stay on the
surface at all times?
The answer is v <= Sqrt[g/(k^2*d)]
Why, and what concepts are involved here?
84. Two pendulums are attached to a massless spring, as shown above. The arms of the pendulums are of identical lengths l, but the pendulum balls have unequal
masses m1 and m2. The initial distance between the masses is the equilibrium length of the spring, which has spring constant K. What is the highest normal
mode frequency of the system?
A. Sqrt[g/l]
B. Sqrt[K/(m1+m2)]
C. Sqrt[K/m1 + K/m2]
D. Sqrt[g/l + K/m1 + K/m2]
E. Sqrt[2g/l + K/(m1+m2)]
The answer is:
D. Sqrt[g/l + K/m1 + K/m2]
My question is why, and how do you know that this frequency is the highest?
the GRE.org website.
83 on GRE. Consider a particle moving without friction on a rippled surface, as shown above. Gravity acts down in the negative h direction. The elevation h(x) of the
surface is given by h(x) = d cos[kx]. If the particle starts at x=0 with a speed v in the x direction, for what values of v will the particle stay on the
surface at all times?
The answer is v <= Sqrt[g/(k^2*d)]
Why, and what concepts are involved here?
84. Two pendulums are attached to a massless spring, as shown above. The arms of the pendulums are of identical lengths l, but the pendulum balls have unequal
masses m1 and m2. The initial distance between the masses is the equilibrium length of the spring, which has spring constant K. What is the highest normal
mode frequency of the system?
A. Sqrt[g/l]
B. Sqrt[K/(m1+m2)]
C. Sqrt[K/m1 + K/m2]
D. Sqrt[g/l + K/m1 + K/m2]
E. Sqrt[2g/l + K/(m1+m2)]
The answer is:
D. Sqrt[g/l + K/m1 + K/m2]
My question is why, and how do you know that this frequency is the highest?